tolong cara dan rumusnya yaa
terimakasihh:)
terimakasihh:)
Jawab :
Penjelasan dengan langkah-langkah :
[tex]\int\limits^2_{-2} {(x+2)(x-1)} \, dx =....\\ (x+2)(x-1) = x^2+x-2\\\int\limits^2_{-2}x^2+x-2 \,dx \\\\\left[\frac{1}{3}x^3+\frac{1}{2}x^2-2x \right]^2_{-2}\\\left[\frac{1}{3}x^3+\frac{1}{2}x^2-2x]^2-\left[\frac{1}{3}x^3+\frac{1}{2}x^2-2x]^-^2 \\\\\\\left[\frac{1}{3}8+\frac{1}{2}4-4]-\left[\frac{1}{3}(-8)+\frac{1}{2}(-4)+4\\[/tex]
[tex]\frac{8}{3}-2-(-\frac{8}{3}-2)\\\frac{8}{3}-(-\frac{8}{3})\\-\frac{16}{3}(A)[/tex]
